# LeetCode 973. K Closest Points to Origin

## Description

https://leetcode.com/problems/missing-ranges/

We have a list of `points` on the plane.  Find the `K` closest points to the origin `(0, 0)`.

(Here, the distance between two points on a plane is the Euclidean distance.)

You may return the answer in any order.  The answer is guaranteed to be unique (except for the order that it is in.)

Example 1:

```Input: points = [[1,3],[-2,2]], K = 1
Output: [[-2,2]]
Explanation:
The distance between (1, 3) and the origin is sqrt(10).
The distance between (-2, 2) and the origin is sqrt(8).
Since sqrt(8) < sqrt(10), (-2, 2) is closer to the origin.
We only want the closest K = 1 points from the origin, so the answer is just [[-2,2]].
```

Example 2:

```Input: points = [[3,3],[5,-1],[-2,4]], K = 2
Output: [[3,3],[-2,4]]
(The answer [[-2,4],[3,3]] would also be accepted.)
```

Note:

1. `1 <= K <= points.length <= 10000`
2. `-10000 < points[i] < 10000`
3. `-10000 < points[i] < 10000`

## Explanation

use a priority queue

## Python Solution

``````from queue import PriorityQueue

class Solution:
def kClosest(self, points: List[List[int]], K: int) -> List[List[int]]:
results = []

distances = []

distances = PriorityQueue()

for point in points:
distance = sqrt(point**2 + point**2)

distances.put((distance, point))

for i in range(0, K):
results.append(distances.get())

return results``````
• Time complexity: ~N
• Space complexity: ~N