# LeetCode 747. Largest Number At Least Twice of Others

## Description

https://leetcode.com/problems/largest-number-at-least-twice-of-others/

You are given an integer array `nums` where the largest integer is unique.

Find whether the largest element in the array is at least twice as much as every other number in the array. If it is, return the index of the largest element, otherwise, return `-1`.

Example 1:

```Input: nums = [3,6,1,0]
Output: 1
Explanation: 6 is the largest integer and for every other number in the array x,
6 is more than twice as big as x.
The index of value 6 is 1, so we return 1.
```

Example 2:

```Input: nums = [1,2,3,4]
Output: -1
Explanation: 4 is not at least as big as twice the value of 3, so we return -1.
```

Constraints:

• `1 <= nums.length <= 50`
• `0 <= nums[i] <= 100`
• The largest element in `nums` is unique.

## Explanation

We can sort first to find if there is a dominant value.

## Python Solution

``````class Solution:
def dominantIndex(self, nums: List[int]) -> int:
if len(nums) < 2:
return 0

sorted_nums = sorted(nums)

if sorted_nums[-1] >= sorted_nums[-2] * 2:
return nums.index(sorted_nums[-1])

return -1``````
• Time Complexity: O(Nlog(N)).
• Space Complexity: O(N).