## Description

https://leetcode.com/problems/count-of-matches-in-tournament/

You are given an integer `n`

, the number of teams in a tournament that has strange rules:

- If the current number of teams is
**even**, each team gets paired with another team. A total of`n / 2`

matches are played, and`n / 2`

teams advance to the next round. - If the current number of teams is
**odd**, one team randomly advances in the tournament, and the rest gets paired. A total of`(n - 1) / 2`

matches are played, and`(n - 1) / 2 + 1`

teams advance to the next round.

Return *the number of matches played in the tournament until a winner is decided.*

**Example 1:**

Input:n = 7Output:6Explanation:Details of the tournament: - 1st Round: Teams = 7, Matches = 3, and 4 teams advance. - 2nd Round: Teams = 4, Matches = 2, and 2 teams advance. - 3rd Round: Teams = 2, Matches = 1, and 1 team is declared the winner. Total number of matches = 3 + 2 + 1 = 6.

**Example 2:**

Input:n = 14Output:13Explanation:Details of the tournament: - 1st Round: Teams = 14, Matches = 7, and 7 teams advance. - 2nd Round: Teams = 7, Matches = 3, and 4 teams advance. - 3rd Round: Teams = 4, Matches = 2, and 2 teams advance. - 4th Round: Teams = 2, Matches = 1, and 1 team is declared the winner. Total number of matches = 7 + 3 + 2 + 1 = 13.

**Constraints:**

`1 <= n <= 200`

## Explanation

Simply implement base on the rules.

## Python Solution

```
class Solution:
def numberOfMatches(self, n: int) -> int:
count = 0
while n > 1:
if n % 2 == 0:
count += n // 2
n = n // 2
else:
count += (n - 1) // 2
n = (n - 1) // 2 + 1
return count
```

- Time Complexity: O(N)
- Space Complexity: O(1)