# LeetCode 1603. Design Parking System

## Description

https://leetcode.com/problems/design-parking-system/

Design a parking system for a parking lot. The parking lot has three kinds of parking spaces: big, medium, and small, with a fixed number of slots for each size.

Implement the `ParkingSystem` class:

• `ParkingSystem(int big, int medium, int small)` Initializes object of the `ParkingSystem` class. The number of slots for each parking space are given as part of the constructor.
• `bool addCar(int carType)` Checks whether there is a parking space of `carType` for the car that wants to get into the parking lot. `carType` can be of three kinds: big, medium, or small, which are represented by `1``2`, and `3` respectively. A car can only park in a parking space of its `carType`. If there is no space available, return `false`, else park the car in that size space and return `true`.

Example 1:

```Input
[[1, 1, 0], [1], [2], [3], [1]]
Output
```

[null, true, true, false, false]

Explanation ParkingSystem parkingSystem = new ParkingSystem(1, 1, 0); parkingSystem.addCar(1); // return true because there is 1 available slot for a big car parkingSystem.addCar(2); // return true because there is 1 available slot for a medium car parkingSystem.addCar(3); // return false because there is no available slot for a small car parkingSystem.addCar(1); // return false because there is no available slot for a big car. It is already occupied.

Constraints:

• `0 <= big, medium, small <= 1000`
• `carType` is `1``2`, or `3`
• At most `1000` calls will be made to `addCar`

## Explanation

Create a dictionary for slot tracking.

## Python Solution

``````class ParkingSystem:

def __init__(self, big: int, medium: int, small: int):
self.slot = {
1: big,
2: medium,
3: small
}

def addCar(self, carType: int) -> bool:
if self.slot[carType] == 0:
return False

self.slot[carType] = self.slot[carType] - 1

return True

# Your ParkingSystem object will be instantiated and called as such:
# obj = ParkingSystem(big, medium, small)