Given an array of numbers
arr. A sequence of numbers is called an arithmetic progression if the difference between any two consecutive elements is the same.
true if the array can be rearranged to form an arithmetic progression, otherwise, return
Input: arr = [3,5,1] Output: true Explanation: We can reorder the elements as [1,3,5] or [5,3,1] with differences 2 and -2 respectively, between each consecutive elements.
Input: arr = [1,2,4] Output: false Explanation: There is no way to reorder the elements to obtain an arithmetic progression.
2 <= arr.length <= 1000
-10^6 <= arr[i] <= 10^6
Sort first. Then compare the differences between numbers.
class Solution: def canMakeArithmeticProgression(self, arr: List[int]) -> bool: arr = sorted(arr) diff = arr - arr prev = arr for num in arr[2:]: if num - prev != diff: return False prev = num return True
- Time Complexity: O(NlogN).
- Space Complexity: O(1).