# LeetCode 1295. Find Numbers with Even Number of Digits

## Description

https://leetcode.com/problems/find-numbers-with-even-number-of-digits/

Given an array `nums` of integers, return how many of them contain an even number of digits.

Example 1:

```Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits).
345 contains 3 digits (odd number of digits).
2 contains 1 digit (odd number of digits).
6 contains 1 digit (odd number of digits).
7896 contains 4 digits (even number of digits).
Therefore only 12 and 7896 contain an even number of digits.
```

Example 2:

```Input: nums = [555,901,482,1771]
Output: 1
Explanation:
Only 1771 contains an even number of digits.
```

Constraints:

• `1 <= nums.length <= 500`
• `1 <= nums[i] <= 10^5`

## Explanation

Calculate the length of number and count even length numbers.

## Python Solution

``````class Solution:
def findNumbers(self, nums: List[int]) -> int:
count = 0
for num in nums:
if len(str(num)) % 2 == 0:
count += 1

return count``````
• Time Complexity: O(N)
• Space Complexity: O(1)