## Description

https://leetcode.com/problems/subtract-the-product-and-sum-of-digits-of-an-integer/

Given an integer number `n`

, return the difference between the product of its digits and the sum of its digits.

**Example 1:**

Input:n = 234Output:15Explanation:Product of digits = 2 * 3 * 4 = 24 Sum of digits = 2 + 3 + 4 = 9 Result = 24 - 9 = 15

**Example 2:**

Input:n = 4421Output:21Explanation:Product of digits = 4 * 4 * 2 * 1 = 32 Sum of digits = 4 + 4 + 2 + 1 = 11 Result = 32 - 11 = 21

**Constraints:**

`1 <= n <= 10^5`

## Explanation

Divide n by digits and calculate product and sum.

## Python Solution

```
class Solution:
def subtractProductAndSum(self, n: int) -> int:
product = 1
sum = 0
while n > 0:
product *= n % 10
sum += n % 10
n = n // 10
return product - sum
```

- Time Complexity: O(1)
- Space Complexity: O(1)