# LeetCode 328. Odd Even Linked List

## Description

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes.

You should try to do it in place. The program should run in O(1) space complexity and O(nodes) time complexity.

Example 1:

```Input: `1->2->3->4->5->NULL`
Output: `1->3->5->2->4->NULL`
```

Example 2:

```Input: 2`->1->3->5->6->4->7->NULL`
Output: `2->3->6->7->1->5->4->NULL`
```

Note:

• The relative order inside both the even and odd groups should remain as it was in the input.
• The first node is considered odd, the second node even and so on …

## Explanation

Create an odd list and an even list, then combine together.

## Python Solution

``````# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
def oddEvenList(self, head: ListNode) -> ListNode:
dummy = ListNode(0)

odd_dummy = ListNode(0)
even_dummy = ListNode(0)

count = 1

odd = odd_dummy
even = even_dummy

while current != None:
if count % 2 == 0:
if count == 2:
even_dummy.next = current
even.next = current
even = even.next
else:
if count == 1:
odd_dummy.next = current
odd.next = current
odd = odd.next

current = current.next

count += 1

even.next = None
odd.next = even_dummy.next
dummy.next = odd_dummy.next

return dummy.next
``````
• Time complexity: O(N).
• Space complexity: O(1).