Description
https://leetcode.com/problems/binary-search/
Given an array of integers nums which is sorted in ascending order, and an integer target, write a function to search target in nums. If target exists, then return its index. Otherwise, return -1.
Example 1:
Input: nums = [-1,0,3,5,9,12], target = 9 Output: 4 Explanation: 9 exists in nums and its index is 4
Example 2:
Input: nums = [-1,0,3,5,9,12], target = 2 Output: -1 Explanation: 2 does not exist in nums so return -1
Constraints:
1 <= nums.length <= 104-9999 <= nums[i], target <= 9999- All the integers in 
numsare unique. numsis sorted in an ascending order.
Explanation
Just implement a basic binary search to search for the target.
Python Solution
class Solution:
    def search(self, nums: List[int], target: int) -> int:
        
        
        start = 0
        end = len(nums) - 1
        
        while start + 1 < end:
            
            mid = start + (end - start) // 2
            
            if nums[mid] == target:
                return mid
            elif nums[mid] > target:
                end = mid
            else:
                start = mid
                
        if nums[end] == target:
            return end
        elif nums[start] == target:
            return start
        
        return -1
- Time Complexity: O(log(N)).
 - Space Complexity: O(1).